Powerball Numbers for Wednesday November 3, 1999
The Powerball winning numbers for the Wednesday November 3, 1999 draw are in! On this page, you can find all the details you need, including the winning numbers, the number of winners, as well as the prizes won. We’ve also included the Double Play draw details. Carefully check your ticket here as you might be one of the winners too!
Winning Numbers
- 1
- 3
- 7
- 8
- 26
- 7
Prize Payouts
| Prize Level | Prize | Winners | Prize Fund Amount |
|---|---|---|---|
| Regular Prizes | |||
| Match 5 plus Powerball | $5,000,000 | 2 | $10,000,000 |
| Match 5 | $100,000 | 14 | $1,400,000 |
| Match 4 plus Powerball | $5,000 | 61 | $305,000 |
| Match 4 | $100 | 1,718 | $171,800 |
| Match 3 plus Powerball | $100 | 1,548 | $154,800 |
| Match 3 | $7 | 51,924 | $363,468 |
| Match 2 plus Powerball | $7 | 16,207 | $113,449 |
| Match 1 plus Powerball | $4 | 70,067 | $280,268 |
| Match 0 plus Powerball | $3 | 96,999 | $290,997 |
| Power Play Prizes | |||
| Totals (Regular & Power Play) | - | 238,540 | $13,079,782 |
The winning tickets were sold in Kentucky and Nebraska and were claimed by William McGaughey (KY) and Charles and Marilyn Anderson (NE). Both winning tickets were claimed using the cash option and received a prize of $2,536,783.36. Charles and Marilyn Anderson selected their own numbers, while William McGaughey chose a Quick Pick.
Facts about this draw
The jackpot for this Powerball draw was $10,000,000, which was a 83.6% decrease in the jackpot amount over the previous draw on October 30 due to it being won. The previous jackpot was $61,100,000.
There were 2 jackpot winners in the November 3, 1999 Powerball drawing. Each ticket won a $5 Million share of the $10 Million jackpot.
The jackpot winning tickets were sold in Kentucky and Nebraska.
